11/7/2022 0 Comments Specific heat of naoh![]() ![]() Many plastics are not capable of holding liquids at 93☌ especially if their density is 1.5kg/L so, as another inferential answer to my question, using a metal container is certainly preferable. Also, I acknowledge that a more accurate result would come about by measuring the actual density of 14M NaOH and using in calculations. 100L in a 200L capacity drum, I would expect that the true 68☌ increase in temperature over ambient to be realized as losses would be small relative to the amount of heat generated. If the 14M was made in a larger quantity e.g. I would suspect that if I made the 14M NaOH solution in a 1L pyrex beaker with open top, losses from the conduction of heat into beaker, radiation from beaker walls and conduction loses from liquid surface would keep the liquid closer to 70-80☌. This value is much closer to the value obtained in the experiment graphic above as well as what I originally measured in the lab. Taking the equation ∆H = mCp∆T and rearranging to solve for NaOH is 38.3wt%)ĭissolving 559.86g NaOH (for 14 M) in 1L of water produces an enthalpy change (∆H) equivalent to -30kJ/mol x 14mol = - 420 kJ. ![]()
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